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Ticket T847065
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Service not registered / overwritten after update from 14.1 to 19.2

created 5 years ago (modified 5 years ago)

Hello,
after updating to DevExpress 19.2. my services gets overwritten at the 'ServiceContainer.Default'-collection.
My class implements two interfaces and registers itself  at 'register()'.

C#
public class MyClass : MyBaseClass, iHostService, iClientService
{
…
protected override void register()
{
string serviceIDHost = "HostSender_MyClassName_2bc3ffb8-f2cd-4672-89cb-8d0f6a9da378"
ServiceContainer.Default.RegisterService( serviceIDHost, this );
string serviceIDClient = "ClientReceiver_MyClassName_6845de3a-3b4d-4b66-ae2c-32743f4227c2"
ServiceContainer.Default.RegisterService( serviceIDClient, this );     // HERE IT GETS OVERWRITTEN?!?
}
}

- How can I register more than one interface to one class with using different keys?

- Are there any changes with key handling to 19.2?

Best regards,
  Alex

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Answers

created 5 years ago

Create separate classes for each interface, e.g. cHostSenderService for iHostService and cClientReceiverService for iClientService, and register each one to the default container:
cCommunicationFactory.removeSpecialServiceID( serviceIDHost,  new cHostSenderService() )
cCommunicationFactory.removeSpecialServiceID( serviceIDClient,  new cClientReceiverService() )

    Comments (1)
    DevExpress Support Team 5 years ago

      Hello Alex,

      Please accept my apologies for not responding in a more timely manner.

      Our service mechanism implementation implies that the same service instance cannot be registered multiple times using different keys. Your code worked because of a bug in the service registration logic until we fixed the bug in versions 15.1\15.2 in the context of a private bug report. Therefore, your solution based on registering different instances using different keys makes sense.

      As for other changes between versions 14.1 and 19.2, please refer to the following Version History pages:

      1. 14.1 - 18.2;
      2. 18.2 - 19.2;

      Please let me know if I can help you with anything else.

      Thanks,
      Michael

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