conditionally lookupview new button disable

Hello Harvinder,

To hide the New button in this editor, create a controller for its lookup ListView and deactivate the New action in it. Here is an example of how to access the master object from this controller:

C#
using System;  
using DevExpress.ExpressApp;  
using DevExpress.ExpressApp.Web.Editors.ASPx;  
using MainDemo.Module.BusinessObjects;  
using DevExpress.ExpressApp.SystemModule;  

namespace MainDemo.Module.Web {  
    public class WebViewController1 : ObjectViewController<ListView, Position> {  
        protected override void OnActivated() {  
            base.OnActivated();  
            if (Frame.Context == TemplateContext.LookupControl && Frame is NestedFrame) {  
                ASPxLookupPropertyEditor lookupPropertyEditor = ((NestedFrame)Frame).ViewItem as ASPxLookupPropertyEditor;  
                if (lookupPropertyEditor != null && lookupPropertyEditor.Model.ParentView.Id == "Department_Contacts_ListView") {  
                    UpdateNewActionVisibility(lookupPropertyEditor);  
                    lookupPropertyEditor.CurrentObjectChanged += lookupPropertyEditor_CurrentObjectChanged;  
                }  
            }  
        }  
        void lookupPropertyEditor_CurrentObjectChanged(object sender, EventArgs e) {  
            UpdateNewActionVisibility((ASPxLookupPropertyEditor)sender);  
        }  
        private void UpdateNewActionVisibility(ASPxLookupPropertyEditor lookupPropertyEditor) {  
            Contact currentContact = lookupPropertyEditor.CurrentObject as Contact;  
            bool addingEnabled = true;  
            if (currentContact != null && currentContact.Department.Title == "SEO") {  
                addingEnabled = false;  
            }  
            Frame.GetController<NewObjectViewController>().NewObjectAction.Active["WebViewController1"] = addingEnabled;  
        }  
    }  
}  

To initialize the new object created by the New button, handle the NewObjectViewController.ObjectCreated event and access the master object in the same manner. See more information in the How to: Initialize an Object Created Using the New Action topic.